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Home » Therefore, the center of the hyperbola is \(\boxed(3, 2)\). - Crankk.io

Therefore, the center of the hyperbola is \(\boxed(3, 2)\). - Crankk.io

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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x^2 + y^2 + rac{3}{4}\left(z + rac{4}{3}
ight)^2 - rac{4}{3} - 4 = 0 \Rightarrow x^2 + y^2 + rac{3}{4}\left(z...
ight)^2 - rac{16}{3} = 0.
Move constant:
ight)^2 = rac{16}{3}.
Divide both sides by $ rac{16}{3} $:
rac{x^2}{rac{64}{9}} + rac{y^2}{rac{64}{3}} + rac{\left(z + rac{4...
ight)^2}{rac{64}{9}} = 1 \quad ext{(after scaling)}.
Actually, write in standard form:
ight)^2}{rac{64}{9}} = 1.

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