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oxed{\left( \dfrac207, \dfrac667 - Crankk.io

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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Multiply through by \( 6400 \) (LCM of 100 and 64):
64x^2 + 100(64 - x^2) = 6400
64x^2 + 6400 - 100x^2 = 6400
-36x^2 = 0 \Rightarrow x^2 = 0
Wait — this suggests only \( x = 0 \), but let's recheck:
Correct substitution:
\frac{x^2}{100} + 1 - \frac{x^2}{64} = 1
x^2\left( \frac{1}{100} - \frac{1}{64} \right) = 0
x^2 \left( \frac{64 - 100}{6400} \right) = 0 \Rightarrow x^2(-36/6400)...
So \( x = 0 \) is the only solution — but this implies the circle is t...

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