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Home » Mouse Clipart That’ll Make Your Designs Stand Out (Free Downloads Inside!) - Crankk.io

Mouse Clipart That’ll Make Your Designs Stand Out (Free Downloads Inside!) - Crankk.io

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 Soit \( x \) le score nécessaire au quatrième examen.

📌 La moyenne est donnée par \( \frac{85 + 90 + 95 + x}{4} = 90 \).

📌 Calculez : \( 270 + x = 360 \).

📌 Résolvez pour \( x \): \( x = 360 - 270 = 90 \).

📌 Un jardin rectangulaire mesure 15 mètres de long et 10 mètres de large. Un chemin de largeur uniforme est construit autour du jardin, augmentant la superficie totale à 264 mètres carrés. Quelle est la largeur du chemin ?

📌 Soit \( x \) la largeur du chemin.

📌 Les nouvelles dimensions sont \( (15 + 2x) \) par \( (10 + 2x) \).

📌 L'équation est \( (15 + 2x)(10 + 2x) = 264 \).

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Question:** A science educator building a model of planetary motion us...
Let \( w = z^3 \). Then the equation becomes:
w^2 + w + 1 = 0
w = \frac{-1 \pm \sqrt{1^2 - 4(1)(1)}}{2} = \frac{-1 \pm \sqrt{-3}}{2}...
So \( z^3 = \omega \) or \( z^3 = \omega^2 \), where \( \omega = e^{2\...
We now solve \( z^3 = \omega \) and \( z^3 = \omega^2 \), each giving...
Let’s find the roots of \( z^3 = \omega \). Write \( \omega = e^{2\pi...
z = \omega^{1/3} \cdot e^{2\pi i k / 3} = e^{2\pi i/9} \cdot e^{2\pi i...
Similarly, for \( z^3 = \omega^2 = e^{-2\pi i/3} \):
z = e^{-2\pi i/9} \cdot e^{2\pi i k / 3} = e^{-2\pi i (1 - 3k)/9} = e^...

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