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📅 February 27, 2026 👤 scraface

Feb 27, 2026

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c = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10
The cosine of the angle \(\theta\) opposite the shorter leg (6 cm) is:
\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{8}{10}...
Thus, the hypotenuse is \(c = 10\) and \(\cos \theta = 0.8\), giving:
\boxed{10, \, 0.8}
A circle is circumscribed around a square with side length \(5 \, \tex...
The diagonal of the square is the diameter of the circumscribed circle...
d = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}
The radius \(r\) of the circle is half the diagonal:
r = \frac{5\sqrt{2}}{2}

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